5q^2-8=2q

Solution for 5q^2-8=2q equation:

5q^2-8=2q

We move all terms to the left:

5q^2-8-(2q)=0

a = 5; b = -2; c = -8;
Δ = b2-4ac
Δ = -22-4·5·(-8)
Δ = 164
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{164}=\sqrt{4*41}=\sqrt{4}*\sqrt{41}=2\sqrt{41}$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{41}}{2*5}=\frac{2-2\sqrt{41}}{10}
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{41}}{2*5}=\frac{2+2\sqrt{41}}{10}
$